working of system.out.println

By: sachin*** On: Sun Feb 16 22:16:14 IST 2014     0 1 0	1
I want to know the Meaning and working of System.out.println(); and reason how out variable call the method println() of printstream class ?	0

 

in System.out.println() System is a class : "public final class System " OUT is :" public final static PrintStream out = null; inside Sytem Class" The "standard" output stream. This stream is already open and ready to accept output data. Typically this stream corresponds to display output. println is a method in :"public class PrintStream extends FilterOutputStream" this method u can use using OUT variable.	0
By: [email protected] On: Mon Feb 17 11:08:15 IST 2014 0 0 0	0
Are You Satisfied :4Yes0No

 

inside the System class is the declaration of ‘out’ that looks like: ‘public static final PrintStream out’, and inside the Prinstream class is a declaration of ‘println()’ that has a method signature that looks like: ‘public void println()’. it could be understand like... import java.io.*; class System{ public static PrintStream out=new PrintStream(); .... } class PrintStream{ public void println(String s){...} public void println(int i){...} public void println(long l){...} ... }	0
By: [email protected] On: Mon Feb 17 12:33:23 IST 2014 0 392 0	392
Are You Satisfied :1Yes0No
Comments
Sir can u give me another example explaining this scenario.
By : [email protected] On: 2014-02-17 13:51:53  0 1 0		1

 

Sir can u give me another example explaining this scenario.	0
By: [email protected] On: Mon Feb 17 13:47:05 IST 2014 0 1 0	1
Are You Satisfied :0Yes0No

 

println() method is used to print and pass the control to the new line. It is a method of PrintStream class. A method is called by the object. Therefore out is the object of the PrintStream class. System is a class that specifies hardware where output is to be produced(here). Thus, output is produced at console.	0
By: [email protected] On: Mon Feb 17 17:18:28 IST 2014 0 359 0	359
Are You Satisfied :0Yes0No